How do you FOIL (Z-2)*(Z-6)(Z2)(Z6)?

1 Answer
Jun 18, 2015

Multiply the First terms then Outside terms then Inside terms then Last terms; sum the result to get Z^2-8Z+12Z28Z+12

Explanation:

Product of
color(white)("XXXX")XXXXF irst terms: Z xx Z = Z^2Z×Z=Z2
color(white)("XXXX")XXXXO utside terms: Z xx (-6) = -6ZZ×(6)=6Z
color(white)("XXXX")XXXXI nside terms: (-2) xx Z = -2Z(2)×Z=2Z
color(white)("XXXX")XXXXL ast terms: (-2) xx (-6) = 12(2)×(6)=12

Sum
color(white)("XXXX")XXXXZ^2 -6Z-2Z+12 = Z^2-8Z+12Z26Z2Z+12=Z28Z+12