How do you graph $- 10 x + 15 y = 60$ $-10x+15y=60$ using intercepts?

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Answer 1 · 2017-08-19T21:57:38

See a solution process below:

x-intercept

To find the $x$ $x$ -intercept we set $y$ $y$ to $0$ $0$ and solve for $x$ $x$ :

$- 10 x + (15 \cdot 0) = 60$ $-10x + (15 * 0) = 60$

$- 10 x + 0 = 60$ $-10x + 0 = 60$

$- 10 x = 60$ $-10x = 60$

$\frac{- 10 x}{- 10} = \frac{60}{- 10}$ $(-10x)/color(red)(-10) = 60/color(red)(-10)$

$(color(red)(cancel(color(black)(-10)))x)/cancel(color(red)(-10)) = -6$

$x = -6$ or $(-6, 0)$

y-intercept

To find the $y$ -intercept we set $x$ to $0$ and solve for $y$ :

$(-10 xx 0) + 15y = 60$

$0 + 15y = 60$

$15y = 60$

$(15y)/color(red)(15) = 60/color(red)(15)$

$(color(red)(cancel(color(black)(15)))y)/cancel(color(red)(15)) = 4$

$y = 4$ or $(0, 4)$

We can now plot the two points and draw a line through them to graph the equation:

graph{((x+6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)(-10x+15y-60)=0}

How do you graph -10x+15y=60−10x+15y=60-10x+15y=60 using intercepts?