How do you graph $2x-1=y$ using the intercepts?

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Answer 1 · 2017-11-02T21:45:46

See a solution process below:

First, solve for the $x$ and $y$ -intercepts and plot these points:

x-intercept - set y = 0 and solve for x:

$2x - 1 = 0$

$2x - 1 + color(red)(1) = 0 + color(red)(1)$

$2x - 0 = 1$

$2x = 1$

$(2x)/color(red)(2) = 1/color(red)(2)$

$x = 1/2$ or $(1/2, 0)$

y-intercept - set x = 0 and solve for y:

$(2 xx 0) - 1 = y$

$0 - 1 = y$

$-1 = y$

$y = -1$ or $(0, -1)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-(1/2))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x-1-y)(x^2+(y+1)^2-0.025)((x-(1/2))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

How do you graph 2x-1=y2x-1=y using the intercepts?