How do you graph 2x-7y=14 using intercepts?
1 Answer
Apr 15, 2018
Explanation:
"to find the intercepts, that is where the graph crosses"
"the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0rArr0-7y=14rArry=-2larrcolor(red)"y-intercept"
y=0rArr2x-0=14rArrx=7larrcolor(red)"x-intercept"
"plot the points "(0,-2)" and "(7,0)
"draw a straight line through them for graph"
graph{(y-2/7x+2)((x-0)^2+(y+2)^2-0.04)((x-7)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}