How do you graph 5x+10y=30 using intercepts?
1 Answer
Apr 27, 2017
see explanation.
Explanation:
"to find the x/y intercepts"
• " let x = 0, in the equation, for y-intercept"
• " let y = 0, in equation, for x-intercept"
x=0to0+10y=30toy=3larrcolor(red)" y-intercept"
y=0to5x+0=30tox=6larrcolor(red)" x-intercept"
"plot the points " (0,3)" and " (6,0) draw a straight line through them and you have the graph.
graph{-1/2x+3 [-10, 10, -5, 5]}