How do you graph $- 5 x + 2 y = 10$ $-5x+2y=10$ using intercepts?

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Answer 1 · 2016-08-26T22:22:08

The intercepts are $(- 2, 0) and (0, 5)$ $(-2, 0) and (0, 5)$

All points along the $x -$ $x-$ axis have their y- value =0.

All points along the $y -$ $y-$ axis have their x- value =0.

To find the $y$ $y$ intercept of a line,make x = 0.

To find the $x$ $x$ intercept of a line,make y = 0.

Once you have the $x - and y -$ $x- and y-$ intercepts, you have two points of the line.

Draw a line which passes through the two points.

$- 5 x + 2 y = 10$ $-5color(red)(x) +2color(blue)(y) = 10$

For $x -$ $x-$ int, $y = 0$ $color(blue)(y=0)$

$\to - 5 x + 2 (0) = 10$ $rarr -5x +2color(blue)((0)) = 10$

$- 5 x = 10 \div - 5$ $-5x = 10" div -5$

$x = \frac{10}{- 5} = - 2 x = - 2$ $x = 10/(-5) = -2 " "x = -2$

For $y -$ $y-$ int, $x = 0$ $color(red)(x=0)$

$\to - 5 (0) x + 2 y = 10$ $rarr -5color(red)((0))x +2y = 10$

$2 y = 10 \div 2$ $2y= 10" "div 2$

$y = \frac{10}{2} = 5 y = 5$ $y = 10/(2) = 5 " "y = 5$

How do you graph -5x+2y=10−5x+2y=10-5x+2y=10 using intercepts?