How do you graph -7y + 2x + 14 using intercepts?

1 Answer
Jul 18, 2017

The equation given is a line. -7y+2x+14=0

Explanation:

We put values for x and get values out for y or vise versa

So we find two point from which the line goes through

Let's start with x=0

-7y+2x+14=0=>-7y+14=0=>y=2

so the first point is A_1(0,2)

Now let's pu y=0

-7y+2x+14=0=>2x+14=0=>x=-7

So the second point is A_2(-7,0)

The graph is a line that goes through A_1 and A_2
graph{-7y+2x+14=0 [-10, 10, -5, 5]}