How do you graph using the intercepts for $-18x + 3y = -12$ ?

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Answer 1 · 2016-02-02T22:24:29

Solve for the intercepts, then draw a straight line between them.

Solving for the intercepts yields:

$-18(0)+3y=-12$
$y=-4$

$-18x+3(0)=-12$
$x=2/3$

So plot the points $(0,-4)$ and $(2/3,0)$ and draw a straight line connecting them.

How do you graph using the intercepts for -18x + 3y = -12-18x + 3y = -12?