Question

How do you graph using the intercepts for `4x-3y=-19`?

Answer 1

`y_("intercept") = +19/3`
`x_("intercept")=-19/4`

Mark you points and draw a straight line through them.

Explanation:

Think about where the graph axis cross. The y-axis is where `x=0` and the x-axis is where `y=0`

To find `y_("intercept")` set `x=0`

`color(brown)(4x-3y=-19)color(blue)(" "->" "4(0)-3y=-19)`

Divide both sides by `(-3)`

`y_("intercept")=(-19)/(-3) = +19/3`
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

To find `x_("intercept")` set `y=0`

`color(brown)(4x-3y=-19)color(blue)(" "->" "4x-3(0)=-19)`

Divide both sides by +4

`x_("intercept")=-19/4`