How do you graph using the intercepts for 4x + 3y = -21?
1 Answer
Jun 12, 2018
Explanation:
"to find the intercepts, that is where the graph crosses"
"the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0rArr3y=-21rArry=-7larrcolor(red)"y-intercept"
y=0rArr4x=-21rArrx=-21/4larrcolor(red)"x-intercept"
"plot the points "(0,-7)" and "(-21/4,0)
"draw a straight line through them for graph"
graph{(y+4/3x+7)((x-0)^2+(y+7)^2-0.04)((x+21/4)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}