Question

How do you graph using the intercepts for `5x+7y=77`?

Answer 1

Plot the points for the x and y intercepts then draw a line through those points.

Explanation:

Given the equation
`color(white)("XXX")5x+7y=77`

The x-intercept is the value of `x` when `y=0`
`color(white)("XXX")5x+7(0)=77`
`color(white)("XXX")rArr x= 15.4`

The y-intercept is the value of `y` when `x=0`
`color(white)("XXX")5(0)+7y=77`
`color(white)("XXX")rArr y= 11`

So the intercept points are at `(15.4,0)` and `(0,11)`

If you plot these two points and draw a straight line through them, your graph should look something like:
graph{((x-15.4)^2 +y^2-0.1)(x^2+(y-11)^2-0.1)(5x+7y-77)=0 [-6.41, 25.63, -3.47, 12.55]}