How do you graph $x+3y=6$ using intercepts?

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Answer 1 · 2017-01-21T13:41:04

Find the intercepts by setting $x=0$ or $y=0$ and solving, then draw a line through them...

Given:

$x+3y = 6$

we can find the intercepts by setting $x=0$ or $y=0$ and solving. This is equivalent to crossing out the term involving $x$ or that involving $y$ .

In any case, putting $x=0$ we have:

$3y = 6$

and hence $y = 6/3=2$

So the intersection with the $y$ axis (which has equation $x=0$ ) is at the point $(0, 2)$

Putting $y=0$ we have:

$x = 6$

So the intersection with the $x$ axis is at $(6, 0)$

Since there are no terms of degree $> 1$ , the given equation describes a line through these two intercepts:

graph{(x+3y-6)(x^2+(y-2)^2-0.02)((x-6)^2+y^2-0.02) = 0 [-7.71, 12.29, -3.8, 6.2]}

How do you graph x+3y=6x+3y=6 using intercepts?