How do you graph x-y=3xy=3 using the x and y intercepts?

1 Answer
May 27, 2017

graph{x-3 [-0.392, 4.62, -3.096, -0.59]}

Explanation:

We can express any linear equation in twotwo variables
in the form
x/axa+y/byb=11
(here the eqeq will be (x/axa-y/byb=33)
1.we want to find where the line intersects the y axis

  1. automatically the valuevalue of xx will become 00
    we are left with -y/byb=33
    by putting b=1b=1 we get y=-3y=3
    the line intersects the y axis at (0,-3)(0,3)
  2. in the same way we can also find out here the line intersects the axis
    it will be (3,0)(3,0)

in terms of plotting the equationequation we will markmark thethe twotwo
points on the x&yx&y and draw a st line throughthrough themthem