How do you graph $y = \sqrt{4 x + 4}$ $y = \sqrt{4x+4}$ ?

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Answer 1 · 2014-11-12T02:34:30

By rewriting a bit,

$y = \sqrt{4 x + 4} = \sqrt{4 (x + 1)} = \sqrt{4} \sqrt{x + 1} = 2 \sqrt{x + 1}$ $y=sqrt{4x+4}=sqrt{4(x+1)}=sqrt{4}sqrt{x+1}=2sqrt{x+1}$

Step 1: Sketching the graph of $y = \sqrt{x}$ $y=sqrt{x}$ .

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Step 2: Sketch the graph of $y = 2 \sqrt{x}$ $y=2sqrt{x}$ by vertically stretching the graph in Step 1 by a factor of $2$ $2$ .

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Step 3: Sketch the graph of $y = 2 \sqrt{x + 1}$ $y=2sqrt{x+1}$ by shifting the graph in Step 2 to the left by 1 unit.

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I hope that this was helpful.

How do you graph y = \sqrt{4x+4}y=√4x+4y = \sqrt{4x+4}?