Question

What is the ordered pair of the origin of the square root function `g(x)=\sqrt{x+4}+6`?

Answer 1

The origin of `y=sqrt{x}` is `(0,0)`.

By shifting left by 4 units, the origin of `y=sqrt{x+4}` moves to `(-4,0)`.

By shifting up by 6 units, the origin of `g(x)=sqrt{x+4}+6` moves to `(-4,6)`. The graph of `y=g(x)` looks like:

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I hope that this was helpful.