What is the ordered pair of the origin of the square root function $g (x) = \sqrt{x + 4} + 6$ $g(x)=\sqrt{x+4}+6$ ?

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What is the ordered pair of the origin of the square root function $g (x) = \sqrt{x + 4} + 6$ $g(x)=\sqrt{x+4}+6$ ?

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Answer 1 · 2014-11-14T23:37:49

The origin of $y = \sqrt{x}$ $y=sqrt{x}$ is $(0, 0)$ $(0,0)$ .

By shifting left by 4 units, the origin of $y = \sqrt{x + 4}$ $y=sqrt{x+4}$ moves to $(- 4, 0)$ $(-4,0)$ .

By shifting up by 6 units, the origin of $g (x) = \sqrt{x + 4} + 6$ $g(x)=sqrt{x+4}+6$ moves to $(- 4, 6)$ $(-4,6)$ . The graph of $y = g (x)$ $y=g(x)$ looks like:

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What is the ordered pair of the origin of the square root function $g (x) = \sqrt{x + 4} + 6$ $g(x)=\sqrt{x+4}+6$ ?

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What is the ordered pair of the origin of the square root function g(x)=\sqrt{x+4}+6g(x)=√x+4+6g(x)=\sqrt{x+4}+6?

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What is the ordered pair of the origin of the square root function $g (x) = \sqrt{x + 4} + 6$ $g(x)=\sqrt{x+4}+6$ ?