How do you integrate ex1exdx?

1 Answer
Dec 17, 2016

2(1xe)323+C

Explanation:

There is one thing to remember when you first look at an integral problem involving substitution:
Which section looks like the derivative of the other.
Since we are dealing with exponental function, this is the simplest problem there is. The derivative of ex=ex.

Seeing that there is a square root, anything that is adding in the root will cause the equation to require a chain rule making this problem difficult therefore. With the substitution, we will make:

u=1ex
du=exdx

Therefore, the final intergral after the substitution is

udu
u12du

Then when you apply the intergral, you add the exponent and then divide the number that you get,

2u323+C

Substitute back the u from the original situation and you have your final answer

2(1xe)323+C