How do you integrate int sec^6(4x)tan(4x)? Calculus Techniques of Integration Integration by Trigonometric Substitution 1 Answer A. S. Adikesavan Dec 8, 2016 sec^6(4x)/24+C Explanation: Use dsecx = sec x tan x dx. int sec^6(4x)tan(4x) dx =1/4 int sec^5(4x)dsec(4x) =sec^6(4x)/24+C Answer link Related questions How do you find the integral int1/(x^2*sqrt(x^2-9))dx ? How do you find the integral intx^3/(sqrt(x^2+9))dx ? How do you find the integral intx^3*sqrt(9-x^2)dx ? How do you find the integral intx^3/(sqrt(16-x^2))dx ? How do you find the integral intsqrt(x^2-1)/xdx ? How do you find the integral intsqrt(x^2-9)/x^3dx ? How do you find the integral intx/(sqrt(x^2+x+1))dx ? How do you find the integral intdt/(sqrt(t^2-6t+13)) ? How do you find the integral intx*sqrt(1-x^4)dx ? How do you prove the integral formula intdx/(sqrt(x^2+a^2)) = ln(x+sqrt(x^2+a^2))+ C ? See all questions in Integration by Trigonometric Substitution Impact of this question 6089 views around the world You can reuse this answer Creative Commons License