How do you integrate $x5^(x^2) dx$ ?

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Answer 1 · 2016-09-03T20:02:34

$1/(2log_e5)5^(x^2)+C$

$d/(dx)(5^(x^2)) = 2 x log_e5 xx 5^(x^2)$ then

$int x5^(x^2) dx = 1/(2log_e5)int d/(dx)(5^(x^2)) = 1/(2log_e5)5^(x^2)+C$

How do you integrate x5^(x^2) dxx5^(x^2) dx?