How do you multiply (2-2x)^4(2−2x)4?

1 Answer
Jammin Bay
Oct 25, 2015

16x^4 + 48x^2+16x+1616x4+48x2+16x+16

Explanation:

(2-2x)^4=(2 - 2x)(2 - 2x)(2 - 2x)(2 - 2x)(2−2x)4=(2−2x)(2−2x)(2−2x)(2−2x)
You should separate them into two, you must use FOIL, (first, outside, inside, last)

(4x^2-4x+4)(4x^2-4x+4)(4x2−4x+4)(4x2−4x+4)

Do it again!

(4x^2*4x^2)+ (4x^2* -4x)+(4x^2*4)+(-4x*4x^2)+(-4x*-4x) + (-4x*4) + (4*4x^2)+(4*-4x)+(4*4)(4x2⋅4x2)+(4x2⋅−4x)+(4x2⋅4)+(−4x⋅4x2)+(−4x⋅−4x)+(−4x⋅4)+(4⋅4x2)+(4⋅−4x)+(4⋅4)

16x^4 - 16x^3 + 16x^2 - 16x^3 + 16x^2 - 16x +16x^2 - 16x + 1616x4−16x3+16x2−16x3+16x2−16x+16x2−16x+16

16x^4 + 48x^2 + 16x + 16 16x4+48x2+16x+16

It's a very long and boring problem which can probably be simplified with some rule.

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