How do you multiply 2(a^2 + a)(3a^2 + 6a)?

1 Answer
Apr 27, 2017

6a^4+18a^3+12a^2

Explanation:

First, apply the distributive property to get:
(2a^2+2a)(3a^2+6a)

Here, you can use FOIL to get all the terms.
F irst --> 2a^2\cdot 3a^2=6a^4
O uter --> 2a^2\cdot 6a=12a^3
I nner --> 2a\cdot 3a^2=6a^3
L ast --> 2a\cdot 6a=12a^2

You then have 6a^4+12a^3+6a^3+12a^2=6a^4+18a^3+12a^2

You can also apply FOIL first and then multiply everything by 2.
2(3a^4+6a^3+3a^3+6a^2)
=2(3a^4+9a^3+6a^2)
=6a^4+18a^3+12a^2