How do you multiply (2r^2+5r-1)(5r^2+2r-8)?
1 Answer
Jun 28, 2018
Explanation:
"each term in the second factor is multiplied by each term"
"in the first factor"
=(color(red)(2r^2+5r-1))(5r^2+2r-8)
=color(red)(2r^2)(5r^2+2r-8)color(red)(+5r)(5r^2+2r-8)
color(white)(=)color(red)(-1)(5r^2+2r-8)
"distributing gives"
=10r^4+4r^3-16r^2+25r^3+10r^2-40r-5r^2-2r+8
"collecting like terms"
=10r^4+29r^3-11r^2-42r+8