(color(red)(2x)-color(blue)(3))(x^2+5^x-3)(2x−3)(x2+5x−3)
=color(red)(2x)(x^2+5^x-3) -color(blue)(3)(x^2+5^x-3)=2x(x2+5x−3)−3(x2+5x−3)
=(color(red)(2x^3+2x*5^x-6x)) - (color(blue)(3x^2+3*5^x-9))=(2x3+2x⋅5x−6x)−(3x2+3⋅5x−9)
=2x^3-3x^2+(2x-3)5^x-6x+9=2x3−3x2+(2x−3)5x−6x+9