How do you multiply $2x(3x^2 - 5)$ ?

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Answer 1 · 2016-07-22T18:01:31

$6x^3 - 10x$

The terms inside the bracket cannot be added or subtracted because they are unlike terms.

We can use the distributive law to multiply the factor outside by each term inside the bracket.

$2x xx 3x^2 - 2x xx5$

= $6x^3 - 10x$

This process is the opposite of factoring.

How do you multiply 2x(3x^2 - 5)2x(3x^2 - 5)?