How do you multiply $(2x+4)(3x^2-5x+7)$ ?

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Answer 1 · 2018-06-28T18:53:46

$6x^3+2x^2-6x+28$

$(2x+4)(3x^2-5x+7)$

$=2x(3x^2-5x+7)+4(3x^2-5x+7)$

$=6x^3-10x^2+14x+12x^2-20x+28$

$=6x^3+2x^2-6x+28$

How do you multiply (2x+4)(3x^2-5x+7)(2x+4)(3x^2-5x+7)?