How do you multiply $(2 x - 4) (x^{2} - 3 x + 10)$ $(2x-4)(x^2 -3x +10)$ ?

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Answer 1 · 2015-07-27T12:27:18

$= 2 x^{3} - 10 x^{2} + 32 x - 40$ $=2x^3 −10x^2 +32x -40$

$(2 x - 4) (x^{2} - 3 x + 10)$ $color(blue)((2x−4))(x^2−3x+10)$

Here, we need to multiply each term within the first bracket with all the three terms of the second bracket.

$= (2 x) (x^{2} - 3 x + 10) - (4) (x^{2} - 3 x + 10)$ $=color(blue)((2x))(x^2−3x+10) −(color(blue)(4))(x^2−3x+10)$

$= 2 x^{3} - 6 x^{2} + 20 x - 4 x^{2} + 12 x - 40$ $=2x^3−6x^2+20x −4x^2 +12x-40$

Grouping like terms
$= 2 x^{3} - 4 x^{2} - 6 x^{2} + 12 x + 20 x - 40$ $=2x^3 −4x^2−6x^2 +12x+20x -40$

$= 2 x^{3} - 10 x^{2} + 32 x - 40$ $=2x^3 −10x^2 +32x -40$

How do you multiply (2x-4)(x^2 -3x +10)(2x−4)(x2−3x+10)(2x-4)(x^2 -3x +10)?