Question

How do you multiply `(2x-5)(x^2+6x-4)`?

Answer 1

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`(color(red)(2x) - color(red)(5))(color(blue)(x^2) + color(blue)(6x) - color(blue)(4))` becomes:

`(color(red)(2x) xx color(blue)(x^2)) + (color(red)(2x) xx color(blue)(6x)) - (color(red)(2x) xx color(blue)(4)) - (color(red)(5) xx color(blue)(x^2)) - (color(red)(5) xx color(blue)(6x)) + (color(red)(5) xx color(blue)(4))`

`2x^3 + 12x^2 - 8x - 5x^2 - 30x + 20`

We can now group and combine like terms:

`2x^3 + 12x^2 - 5x^2 - 8x - 30x + 20`

`2x^3 + (12 - 5)x^2 + (-8 - 30)x + 20`

`2x^3 + 7x^2 - 38x + 20`