How do you multiply $[(2z + r) +1]^2$ ?

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Answer 1 · 2018-08-06T10:47:00

$4z^2+r^2+4zr+4z+2r+1$

$[(2z+r)+1]^2=((2z+r)+1)((2z+r)+1)$

$"expand factors using FOIL"$

$=(2z+r)^2+2(2z+r)+1$

$=4z^2+4zr+r^2+4z+2r+1$

$=4z^2+r^2+4zr+4z+2r+1$

How do you multiply [(2z + r) +1]^2[(2z + r) +1]^2?