How do you multiply $(3-y^6)(3-y^6)$ ?

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Answer 1 · 2015-10-10T22:00:55

$9-6y^6 + y^12$

Use the technique FOIL (First Outer Inner Last) to evaluate the multiplication.

First:

$3*3 = 9$

Outer:

$3* - y^6 = -3y^6$

Inner:

$-y^6 * 3 = -3y^6$

Last:

$y^6 *y^6 = y^12$

Now add all the products:

$9 -3y^6 - 3y^6 + y^12 = 9-6y^6 + y^12$

We reach our answer this way.

Hopefully this helped!

How do you multiply (3-y^6)(3-y^6)(3-y^6)(3-y^6)?