How do you multiply $(3 t^{2} - 2 t - 4) (5 t + 9)$ $(3t^2 -2t -4)(5t+9)$ ?

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Answer 1 · 2015-07-06T19:48:46

$15 t^{3} + 17 t^{2} - 38 t - 36$ $15t^3 + 17t^2 - 38t - 36$

$3 t^{2} (5 t + 9) - 2 t (5 t + 9) - 4 (5 t + 9)$ $3t^2(5t + 9) -2t (5t + 9) - 4(5t + 9)$

$= 15 t^{3} + 27 t^{2} - 10 t^{2} - 18 t - 20 t - 36$ $= 15t^3 + 27t^2 - 10t^2 - 18t - 20t - 36$

How do you multiply (3t^2 -2t -4)(5t+9)(3t2−2t−4)(5t+9)(3t^2 -2t -4)(5t+9)?