How do you multiply ${(3 u^{2} - n)}^{2}$ $(3u^2 - n)^2$ ?

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Answer 1 · 2018-04-10T21:30:41

$9 u^{4} - 6 u^{2} + n^{2}$ $9u^4-6u^2+n^2$

$(3 u^{2} - n) (3 u^{2} - n)$ $(3u^2-n)(3u^2-n)$

$9 u^{4} - 3 u^{2} n - 3 u^{2} n + n^{2}$ $9u^4-3u^2n-3u^2n+n^2$

$9 u^{4} - 6 u^{2} + n^{2}$ $9u^4-6u^2+n^2$

How do you multiply (3u^2 - n)^2(3u2−n)2(3u^2 - n)^2?