How do you multiply (3x^2 + 2x + 4)(2x + 1)?

2 Answers
Apr 24, 2018

6x^3+7x^2+ 10x +4

Explanation:

You have to take each number in the first bracket and multiply it by the second one.
First lets do 3x^2
(3x^2)*(2x) and (3x^2)*1 This will give 6x^3 and 3x^2#

Then 2x
2x * 2x and 2x *1
This will give 4x^2 and 2x

Then 4
4*2x and 4*1
This will give 8x and 4

Taking all these, you simply just add them together!

Apr 24, 2018

= 6x^3 + 7x^2+10x+4

Explanation:

Do the first term in the first bracket multiplied by the first term in the second bracket. Do the same with the first term in the first bracket (3x^2) and the second term of the second bracket.

(3x^2)x(2x) = 6x^3
(3x^2)x(1) = 3x^2

[For powers, use the rule:

a^mxa^n = a^m+n (where x is actually x^1 from example above which simply calculates to x)

Then multiply any real numbers as you normally would (3x2)]

For the next step, multiply the second term of the first bracket to the first of the second bracket:

(2x)x(2x) = 4x^2
(2x)x(1) = 2x

Proceed to the final term in the first bracket and follow the same steps:

(4)x(2x) = 8x
(4)x(1) = 4

Simplify by adding all like terms together:

= 6x^3 +3x^2+4x^2+2x+8x+4
= 6x^3 + 7x^2+10x+4

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