How do you multiply ${(3 x + 4)}^{2}$ $(3x + 4)^2$ ?

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How do you multiply ${(3 x + 4)}^{2}$ $(3x + 4)^2$ ?

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Answer 1 · 2015-08-23T11:04:30

$= 9 x^{2} + 24 x + 16$ $=color(blue)(9x^2+24x+16$

Explanation:

${(3 x + 4)}^{2} = (3 x + 4) \cdot (3 x + 4)$ $(3x+4)^2 = color(blue)((3x+4)) * (3x+4)$

$= (3 x) \cdot (3 x + 4) + (4) (3 x + 4)$ $= color(blue)((3x)) * (3x+4) +color(blue)((4))(3x+4)$
$= 9 x^{2} + 12 x + 12 x + 16$ $=9x^2+12x+12x+16$
$= 9 x^{2} + 24 x + 16$ $=color(blue)(9x^2+24x+16$

Note:
The property: ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $color(blue)((a+b)^2=a^2+2ab+b^2$ can be applied to the same expression

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How do you multiply ${(3 x + 4)}^{2}$ $(3x + 4)^2$ ?

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