How do you multiply $(3 x + 8 y) (x - 2 y)$ $(3x+8y)(x-2y)$ ?

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How do you multiply $(3 x + 8 y) (x - 2 y)$ $(3x+8y)(x-2y)$ ?

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Answer 1 · 2018-07-02T21:29:24

$3 x^{2} + 2 x y - 16 y^{2}$ $3x^2+2xy-16y^2$

Explanation:

$each term in the second factor is multiplied by each term$ $"each term in the second factor is multiplied by each term"$
$in the first factor$ $" in the first factor"$

$(3 x + 8 y) (x - 2 y)$ $(color(red)(3x+8y))(x-2y)$

$= 3 x (x - 2 y) + 8 y (x - 2 y) \leftarrow distribute$ $=color(red)(3x)(x-2y)color(red)(+8y)(x-2y)larrcolor(blue)"distribute"$

$= 3 x^{2} - 6 x y + 8 x y - 16 y^{2} \leftarrow collect like terms$ $=3x^2color(blue)(-6xy)color(blue)(+8xy)-16y^2larrcolor(magenta)"collect like terms"$

$= 3 x^{2} + 2 x y - 16 y^{2}$ $=3x^2+2xy-16y^2$

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How do you multiply $(3 x + 8 y) (x - 2 y)$ $(3x+8y)(x-2y)$ ?

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How do you multiply $(3 x + 8 y) (x - 2 y)$ $(3x+8y)(x-2y)$ ?