How do you multiply $4(3x+1) (x-2)$ ?

Question

1675 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-06T21:14:49

Start by FOILing the two binomials:
$4(3x+1)(x-2)$
$4(3x^2 -6x + x -2)$
$4(3x^2 - 5x -2)$
Distribute the $4$ to all the terms:
$12x^2 - 20x -8$

How do you multiply 4(3x+1) (x-2)4(3x+1) (x-2)?