How do you multiply $(4 + x) (4 - x)$ $(4+x)(4-x)$ ?

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Answer 1 · 2016-08-03T06:30:00

$16 - x^{2}$ $16-x^2$

$(4 + x) (4 - x)$ $(4+x)(4-x)$ $=$ $=$ $4 (4 - x) + x (4 - x)$ $4(4-x)+x(4-x)$

$=$ $=$ $16-cancel(4x)+cancel(4x)-x^2$

$=$ $-x^2+16$

How do you multiply (4+x)(4-x)(4+x)(4−x)(4+x)(4-x)?