How do you multiply $(-4m^2-3n)^2$ ?

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Answer 1 · 2017-08-21T10:41:44

See a solution process below:

We can use this rule to multiply this expression:

$(color(red)(x) + color(blue)(y))^2 = color(red)(x)^2 + 2color(red)(x)color(blue)(y) + color(blue)(y)^2$

Substituting $color(red)(-4m^2)$ for color(red)(x) and substituting $color(blue)(-3n)$ for $color(blue)(y)$ gives:

$(color(red)(-4m^2) + color(blue)(-3n))^2 =>$

$color(red)((-4m^2))^2 + (2 * color(red)(-4m^2) * color(blue)(-3n)) + color(blue)((-3n))^2 =>$

$16m^4 + 24m^2n + 9n^2$

How do you multiply (-4m^2-3n)^2(-4m^2-3n)^2?