How do you multiply $(4u+7v)^2$ ?

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Answer 1 · 2016-08-19T00:56:30

$(4u+7v)^2=16u^2+56uv+49v^2$

$(4u+7v)^2$

= $(4u+7v)(4u+7v)$

= $4u(4u+7v)+7v(4u+7v)$

= $4u×4u+4u×7v+7v×4u+7v×7v$

= $16u^2+28uv+28uv+49v^2$

= $16u^2+56uv+49v^2$

How do you multiply (4u+7v)^2(4u+7v)^2?