How do you multiply $(4x^2-7)(x^2+4)$ ?

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Answer 1 · 2017-02-19T11:34:35

$4x^4+9x^2-28$

You would multiply the polynomials term by term and get four monomials:

$4x^2*x^2+4x^2*4-7*x^2-7*4=4x^4+16x^2-7x^2-28$

and add the like terms:

$4x^4+9x^2-28$

How do you multiply (4x^2-7)(x^2+4)(4x^2-7)(x^2+4)?