How do you multiply $4 x (3 x^{2} + 2 x + 1)$ $4x(3x^2+2x+1)$ ?

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How do you multiply $4 x (3 x^{2} + 2 x + 1)$ $4x(3x^2+2x+1)$ ?

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Answer 1 · 2015-06-24T15:33:05

$= 12 x^{3} + 8 x^{2} + 4 x$ $= color(blue)( 12x^3 + 8x^2 +4x$

Explanation:

$4 x (3 x^{2} + 2 x + 1)$ $color(blue)(4x)(3x^2 + 2x +1)$
Here $4 x$ $color(blue)(4x)$ needs to be multiplied with each term within bracket:

$= 4 x . (3 x^{2}) + 4 x . (2 x) + 4 x . (1)$ $=color(blue)(4x) . (3x^2 ) + color(blue)(4x).(2x) +color(blue)(4x).(1)$
$= 12 x^{3} + 8 x^{2} + 4 x$ $= color(blue)( 12x^3 + 8x^2 +4x$

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How do you multiply $4 x (3 x^{2} + 2 x + 1)$ $4x(3x^2+2x+1)$ ?

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How do you multiply 4x(3x^2+2x+1) 4x(3x2+2x+1)4x(3x^2+2x+1) ?

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How do you multiply $4 x (3 x^{2} + 2 x + 1)$ $4x(3x^2+2x+1)$ ?