How do you multiply #4x(3x^2+2x+1) #? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Don't Memorise Jun 24, 2015 # = color(blue)( 12x^3 + 8x^2 +4x# Explanation: #color(blue)(4x)(3x^2 + 2x +1)# Here # color(blue)(4x)# needs to be multiplied with each term within bracket: #=color(blue)(4x) . (3x^2 ) + color(blue)(4x).(2x) +color(blue)(4x).(1) # # = color(blue)( 12x^3 + 8x^2 +4x# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1360 views around the world You can reuse this answer Creative Commons License