How do you multiply (4x + 5)^2?

4 Answers
Nov 27, 2017

16x^2+40x+25

Explanation:

(4x+5)^2=(4x+5)(4x+5)

"each term in the second factor is multiplied by "
"each term in the first factor"

rArr(color(red)(4x+5))(4x+5)

=color(red)(4x)(4x+5)color(red)(+5)(4x+5)

"distribute each product"

=16x^2+20x+20x+25

=16x^2+40x+25larrcolor(blue)"collect like terms"

Nov 27, 2017

16x^2+40x+25

Explanation:

Use the FOIL method, or the shortcut for squaring binomials.

For any x and y, (x+y)^2=x^2+2xy+y^2

Our x is 4x and our y is 5.

Therefore:

(4x+5)^2=(4x)^2+2(4x*5)+(5)^2

(4x+5)^2=16x^2+40x+25

Alternatively, you could multiply 'each by each,' using the FOIL method.

Nov 27, 2017

See a solution process below:

Explanation:

We can use this rule for quadratics:

(color(red)(x) + color(blue)(y))^2 = (color(red)(x) + color(blue)(y))(color(red)(x) + color(blue)(y)) = color(red)(x)^2 + 2color(red)(x)color(blue)(y) + color(blue)(y)^2

Let:

color(red)(x) = 4x

color(blue)(y) = 5

Substituting gives:

(color(red)(4x) + color(blue)(5))^2 =>

(color(red)(4x) + color(blue)(5))(color(red)(4x) + color(blue)(5)) =>

16x^2 + 40x + 25

Nov 27, 2017

=16x^2 + 40x + 25

Explanation:

(4x + 5)^2

As you can see, each users are solving it differently and this is what makes Math funny and unique. There are different steps, strategies you can use to solve a problem.

Well, I'm gonna use my favorite method which is Distributive

So let's start:

=(4x)(4x)+(4x)(5)+(5)(4x)+(5)(5)

=16x^2 + 20x + 20x + 25

=16x^2 + 40x + 25