How do you multiply $4y(2y-3)-5(2-y)$ ?

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Answer 1 · 2015-06-26T13:44:29

$= color(blue)(8y^2 - 7y -10)$

$color(blue)(4y)(2y-3)-color(green)(5)(2-y)$

$= [color(blue)(4y) . (2y) + color(blue)(4y) . (-3)] - [color(green)(5).(2) +color(green)(5).(-y)]$

$= color(blue)(8y^2 - 12y) - color(green)(10 + 5y)$
combining
$= color(blue)(8y^2 - 7y -10)$

How do you multiply 4y(2y-3)-5(2-y)4y(2y-3)-5(2-y)?