How do you multiply $(6x-3) (4x+33)$ ?

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Answer 1 · 2016-12-14T21:00:32

$24x^2 + 186x - 99$

You need to cross multiply each term in the parenthesis on the left by each term in the parenthesis on the right and then group like terms:

$(6x*4x) + (6x*33) - (3*4x) - (3*33)$

$24x^2 + 198x - 12x - 99$

$24x^2 + (198 - 12)x - 99$

$24x^2 + 186x - 99$

How do you multiply (6x-3) (4x+33)(6x-3) (4x+33)?