How do you multiply $(7 - 8 x) (7 + 8 x)$ $(7-8x)(7+8x)$ ?

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Answer 1 · 2015-12-03T07:50:32

$= 49 - 64 x^{2}$ $=color(blue)(49-64x^2$

$(7 - 8 x) (7 + 8 x)$ $(7−8x)(7+8x)$

Upon observation it can be noticed that the expression is of the form:

$(a - b) (a + b) = a^{2} - b^{2}$ $color(blue)((a-b)(a+b) = a^2-b^2$

So, in the given expression:

$7 = a and 8 x = b$ $7=color(blue)(a) and 8x=color(blue)(b$

$(7 - 8 x) (7 + 8 x) = 7^{2} - {(8 x)}^{2}$ $(7−8x)(7+8x) = 7^2-(8x)^2$

$= 49 - 64 x^{2}$ $=color(blue)(49-64x^2$

How do you multiply (7-8x)(7+8x)(7−8x)(7+8x)(7-8x)(7+8x)?