How do you multiply $(7x+3) (7x+3)$ ?

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Answer 1 · 2015-08-21T03:32:06

$(7x+3)(7x+3)=(7x+3)^2=49x^2+42x+9$

$(7x+3)(7x+3)=(7x+3)^2$

$(7x+3)^2$ is the square of a sum with the form $(a+b)^2=a^2+2ab+b^2$ , where $a=7x$ and $b=3$ .

$(7x+3)^2=(7x)^2+(2*7x*3)+(3)^2$ $=$

$(7x+3)^2=49x^2+42x+9$

You could also use the FOIL method.

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$(7x+3)(7x+3)=(7x*7x)+(7x*3)+(3*7x)+(3*3)$ $=$

$(7x+3)(7x+3)=49x^2+21x+21x+9$ $=$

$(7x+3)(7x+3)=49x^2+42x+9$

How do you multiply (7x+3) (7x+3)(7x+3) (7x+3)?