How do you multiply $(7 z + 6) (3 z + 3)$ $(7z+6)(3z+3)$ ?

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Answer 1 · 2015-08-19T12:43:52

$= 21 z^{2} + 39 z + 18$ $=color(blue)(21z^2 + 39z +18$

$(7 z + 6) (3 z + 3)$ $color(blue)( (7z+6))(3z+3)$

$= (7 z) (3 z) + (7 z) (3) + 6 (3 z) + 6 (3)$ $=color(blue)( (7z))(3z) + color(blue)( (7z))(3) +color(blue)(6)(3z) + color(blue)(6)(3)$

$= 21 z^{2} + 21 z + 18 z + 18$ $=21z^2 + 21z + 18z +18$
$= 21 z^{2} + 39 z + 18$ $=color(blue)(21z^2 + 39z +18$

How do you multiply (7z+6)(3z+3)(7z+6)(3z+3)(7z+6)(3z+3)?