How do you multiply $(8p-2)(6p+2)$ ?

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Answer 1 · 2015-07-11T06:13:20

$(8p-2)(6p+2)=48p^2+4p-4$

Use the FOIL method which indicates the order in which the terms of each binomial are multiplied.

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$(8p-2)(6p+2)$ =

$(8p*6p)+(8p*2)+(-2*6p)+(-2*2)$ =

$48p^2+16p-12p-4$ =

$48p^2+4p-4$

How do you multiply (8p-2)(6p+2) (8p-2)(6p+2) ?