How do you multiply $(8 y^{6} + 4 y^{4} - 12 y^{2}) (\frac{3}{4} y^{2} + 2)$ $(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)$ ?

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How do you multiply $(8 y^{6} + 4 y^{4} - 12 y^{2}) (\frac{3}{4} y^{2} + 2)$ $(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)$ ?

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Answer 1 · 2015-08-25T16:33:44

$6 y^{8} + 19 y^{6} - y^{4} - 24 y^{2}$ $6y^8 +19y^6 - y^4 - 24y^2$

Explanation:

$\frac{24}{4} y^{8} + \frac{12}{4} y^{6} - \frac{36}{4} y^{4} + 16 y^{6} + 8 y^{4} - 24 y^{2}$ $24/4y^8+12/4y^6-36/4y^4+16y^6+8y^4-24y^2$
$6 y^{8} + 3 y^{6} - 9 y^{4} + 16 y^{6} + 8 y^{4} - 24 y^{2}$ $6y^8 + 3y^6 -9y^4 + 16y^6 + 8y^4 - 24y^2$
$6 y^{8} + 19 y^{6} - y^{4} - 24 y^{2}$ $6y^8 +19y^6 - y^4 - 24y^2$

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How do you multiply $(8 y^{6} + 4 y^{4} - 12 y^{2}) (\frac{3}{4} y^{2} + 2)$ $(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)$ ?

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How do you multiply (8y^6 + 4y^4 -12y^2) (3/4y^2 +2)(8y6+4y4−12y2)(34y2+2)(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)?

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How do you multiply $(8 y^{6} + 4 y^{4} - 12 y^{2}) (\frac{3}{4} y^{2} + 2)$ $(8y^6 + 4y^4 -12y^2) (3/4y^2 +2)$ ?