How do you multiply $(a+2) (a^2- 3a+7)$ ?

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Answer 1 · 2015-07-27T12:18:15

$=color(blue)(a^3 -a^2 +a+14$

$color(blue)((a+2))(a^2−3a+7)$

Here, we need to multiply each term within first bracket with the three terms of the second bracket.

$=color(blue)((a))(a^2−3a+7))+ color(blue)((2))(a^2−3a+7)$

$=a^3 -3a^2 +7a+ 2a^2 -6a+14$

grouping like terms

$=a^3 +( 2a^2-3a^2) +(7a-6a)+14$
$=color(blue)(a^3 -a^2 +a+14$

How do you multiply (a+2) (a^2- 3a+7)(a+2) (a^2- 3a+7)?