How do you multiply ${(b - 7)}^{2}$ $(b-7)^2$ ?

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How do you multiply ${(b - 7)}^{2}$ $(b-7)^2$ ?

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Answer 1 · 2016-06-18T15:41:23

${(b - 7)}^{2} = b^{2} - 14 b + 49$ $(b-7)^2=b^2-14b+49$

Explanation:

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a-b)^2=a^2-2ab+b^2$
same concept
${(b - 7)}^{2} = b^{2} - 2 \cdot b \cdot 7 + 7^{2}$ $(b-7)^2=b^2-2*b*7+7^2$
$= b^{2} - 14 b + 49$ $=b^2-14b+49$

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How do you multiply ${(b - 7)}^{2}$ $(b-7)^2$ ?

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