How do you multiply $(- d + 4) (- d - 4)$ $(-d + 4)(-d - 4)$ ?

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Answer 1 · 2018-03-02T04:15:18

USE FOIL

F- first terms meaning multiply $- d \cdot - d = d^{2}$ $-d * -d = d^2$

O- outside meaning $- d \cdot - 4 = 4 d$ $-d * -4=4d$

I- inside meaning $4 \cdot - d = - 4 d$ $4*-d=-4d$

& finally

L - last meaning $4 \cdot - 4 = - 16$ $4 * -4= -16$

Now add all answers $d^{2} + 4 d + - 4 d \pm 16$ $d^2 + 4d + -4d +-16$

Which gives $d^{2} - 16$ $d^2 -16$

ANS = $d^{2} - 16$ $d^2-16$

How do you multiply (-d + 4)(-d - 4)(−d+4)(−d−4)(-d + 4)(-d - 4)?